Since we are integrating the input then we want:
\begin{equation} C_{T}=C_{f} s \end{equation}The capacitor must hold the maximum possible charge from the diode which is defined by the maximum energy out: 2e-09[J] and the Conversion Factor of the diode: 0.05[A/W] so the max charge ($Q_{max}$)is: 1e-10[C]
I need the Capacitor but I am not sure of the Max output voltage; if I allow room for crosstalk and charge injection then I could safely assume $V_{max}=$2.5[V] so $C_f=\frac{Q_{max}}{V_{max}}$ and:
\begin{equation} C_{f}=40.0\,\left[ \mathrm{pF}\right] \end{equation}Go to Circuit-Configuration-Analysis_index
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Last project update: 2022-11-20 18:08:04