The Maximum Power from the Pin Diode is: 0.02[W] the gain conversion is: 0.05[A/W]
This means the Op Amp must be able to copy that current through the feedback capacitor, so the feedback capacitor will determine the show stopper drive current:
\begin{equation} \frac{dV}{dt}=25.0\,\left[ \mathrm{\frac{V}{\mu s}}\right] \end{equation}The Offset voltage is determined by the sum of the maximum integration time of the dark current 2e-06[s] and the Voltage from the charge injection of the switch 1.5e-12[C]
\begin{equation} V_{offset}=0.04\,\left[ \mathrm{V}\right] \end{equation}With a Dark Current of :5e-08[A] we need more to bias the op amp. With $V_{max}=$2.5and allowing room for power supply noise and inaccuracy a maximum bias current is:
\begin{equation} I_{b}=1.275 \cdot 10^{-5}\,\left[ \mathrm{A}\right] \end{equation}Go to index
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Last project update: 2022-11-20 18:08:04